4m^2/3=100

Solution for 4m^2/3=100 equation:

4m^2/3=100

We move all terms to the left:

4m^2/3-(100)=0

We multiply all the terms by the denominator


4m^2-100*3=0

We add all the numbers together, and all the variables

4m^2-300=0

a = 4; b = 0; c = -300;
Δ = b2-4ac
Δ = 02-4·4·(-300)
Δ = 4800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4800}=\sqrt{1600*3}=\sqrt{1600}*\sqrt{3}=40\sqrt{3}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{3}}{2*4}=\frac{0-40\sqrt{3}}{8}
=-\frac{40\sqrt{3}}{8}
=-5\sqrt{3}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{3}}{2*4}=\frac{0+40\sqrt{3}}{8}
=\frac{40\sqrt{3}}{8}
=5\sqrt{3}
$